ln(y)=ln(1+x^2)+c

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Solution for ln(y)=ln(1+x^2)+c equation: 


Simplifying
ln(y) = ln(1 + x2) + c

Multiply ln * y
lny = ln(1 + x2) + c
lny = (1 * ln + x2 * ln) + c
lny = (1ln + lnx2) + c

Reorder the terms:
lny = c + 1ln + lnx2

Solving
lny = c + 1ln + lnx2

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '-1ln' to each side of the equation.
-1ln + lny = c + 1ln + -1ln + lnx2

Combine like terms: 1ln + -1ln = 0
-1ln + lny = c + 0 + lnx2
-1ln + lny = c + lnx2

Add '-1lnx2' to each side of the equation.
-1ln + -1lnx2 + lny = c + lnx2 + -1lnx2

Combine like terms: lnx2 + -1lnx2 = 0
-1ln + -1lnx2 + lny = c + 0
-1ln + -1lnx2 + lny = c

Reorder the terms:
-1c + -1ln + -1lnx2 + lny = c + -1c

Combine like terms: c + -1c = 0
-1c + -1ln + -1lnx2 + lny = 0

The solution to this equation could not be determined.

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